Find out whether Word was launched from its shortcut or by double-clicking a file
Article contributed by Will Rickards and Dave Rado
Option Explicit
Public Declare Function
GetCommandLine
Lib "kernel32" _
Alias
"GetCommandLineA" () As Long
Public Declare Function lstrcpy
Lib
"kernel32" _
Alias "lstrcpyA"
(ByVal
lpString1 As String,
ByVal
lpString2 As Long) As
Long
Public Declare Function lstrlen
Lib
"kernel32" _
Alias "lstrlenA"
(ByVal
lpString As Long) As
Long
Public Sub AutoExec()
Dim strCommandLine As String
'get the command line using CmdLinetoString function and GetCommandLine API call
strCommandLine = CmdLinetoString(GetCommandLine())
If Len(strCommandLine) <= Len(Chr(34) & Application.Path & "\" & _
"winword.exe" & Chr(34) & " ")
Then
Msgbox " Word was launched from its shortcut"
Else
Msgbox " Word was launched by opening a file"
End If
End Sub
Public Function CmdLinetoString(ByVal
lngPtr
As Long) As String
Dim strReturn
As String
Dim StringLength
As Long
'get the length of the string (not including the terminating
null character)
StringLength = lstrlen(lngPtr)
'initialize our string so it has enough characters including
the null character
strReturn = String$(StringLength + 1, 0)
'copy the string we have a pointer to into our new string
lstrcpy strReturn, lngPtr
'now strip off the null character at the end
strReturn = Left$(strReturn, StringLength)
'return the string
CmdLinetoString = strReturn
End Function
